Question

A set contains the first 10 natural numbers, except
one of them. If the average of the set is 5 4/9, find
the number which is missed?

​

Answer 1

Step-by-step explanation:

average of 9 numbers = 5 4/9

sum of all observation =

$9 \times 5 \frac{4}{9} = 9 \times \frac{49}{9} = 49$

sum of all observation of 10 numbers

= 1+2+3+4+5+6+7+8+9+10 = 55

missing number = 55 - 49 = 6