A set of 4 consecutive intergers has a sum of 110
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Answer:
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Step-by-step explanation:
26+27+28+29 this are the nos.
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35
Correct Question :-----
- A set of 4 consecutive natural numbers has a sum of 110 ... Find the numbers ?
Let the 4 consecutive natural numbers be = x, x+1, x+2 and x+3...
A/q,
x + (x+1) + (x+2) + (x+3) = 110
→ 4x + 6 = 110
→ 4x = 110 - 6
→ 4x = 104
→ x = 104/4 = 26 First number.
x+1 = 26+1 = 27
x+2 = 26+2 = 28
x+3 = 26 + 3 = 29
Hence , required set is {26, 27, 28, 29}
(Hope it helps you)
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