A set of 6 motors is connected in series to a 120 V source drawing 1.0 A of current. Find:
a) R total
b) R of each motor
c) Voltage drop across each load.
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6 motors of resistance R each
then in series the equivalent resistance is 6R
current is given as 1A
given voltage is 120 V
so 6R=120/1 => R = 20 ohms each
so total Resistance = 6 R = 120 ohms
for each load voltage drop = iR = 1x20 = 20 V
then in series the equivalent resistance is 6R
current is given as 1A
given voltage is 120 V
so 6R=120/1 => R = 20 ohms each
so total Resistance = 6 R = 120 ohms
for each load voltage drop = iR = 1x20 = 20 V
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