Question

A = (set of all factors of 24} B = {set of all factors of 36) VERIFY THE FORMULA, n(AUB) = n(A) + n(B)-N(ANB)​

Answer 1

Step-by-step explanation:

We have,

A = {4, 6, 9, 15, 20, 21}

B= {6, 15, 20, 23}

Now,

AUB = all the elements of A and B

= {4, 6, 9, 15, 20, 21, 23}

and AnB = all the common elements of A and B

= { 6, 15, 20}

Now,

n (A) =6, n (B) = 4

n (AUB) = 7 and n (AnB) =3

Now,

n (A) + n (B) =10

n (AUB) + n (AnB) =10

So, n (A) + n (B) = n (AUB) + n (AnB)