Question

A set of figures carrying certain numbers, is given.
Assuming that the number in each set follows a similar
pattern, find the missing number.
(15) (2)
(80)
(5) (6)

(9) (7)
(65)
(4) (6)

(13) (16)
(?)
(11) (8)

A. 35
B. 48
C. 72
D. 120​

Answer 1

Answer:

your answer is b) 48

Step-by-step explanation:

In first pattern

15 - 5 × 2 + 6 =80

In second pattern

9-4 × 7+6=65

In third pattern

13-11× 16+8 =48

hope it helps u

Answer 2

The missing number is 48.

Given -

The given sets of figures are showing a pattern of multiples. In the first set, the numbers are multiples of 5: 15, 20, 25, 30, 35.

In the second set, the numbers are multiples of 6: 6, 12, 18, 24, 30, 36. In the third set, the numbers are multiples of 8: 8, 16, 24, 32, 40.

To find -

The missing number.

Solution -

We can see that in all the sets, the number in the middle is the multiple of the first and last numbers of the set.

• In the first set, the first number is 15 and the last number is 6, so the middle number is 25 which is 5 times 5.
• In the second set, the first number is 9 and the last number is 6, so the middle number is 18 which is 3 times 6.
• In the third set, the first number is 13 and the last number is 8, so the middle number is 24 which is 3 times 8.

Applying this pattern to the question, the first number is 16 and the last number is 11, so the middle number is

(16*11)/2 = 88/2 = 44.

So the missing number is 48.

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