Question

A set of five different positive integers as a mean of 20 and a median of 18 . what is the greatest possible integer in the set?​

Answer 1

Answer:

I have attached the answer . Please mark me as brainliast . Hope it helps.

Step-by-step explanation:

Please mark me as brainliast. Hope it helps.

Answer 2

The greatest possible integer in the set is 56. The set itself is {1, 2, 18, 3, 56}.

Let's call the five positive integers in the set a, b, c, d, and e.

Since the median of the set is 18, we know that either c or d must be 18 (or both).

Without loss of generality, let's assume that c = 18.

We also know that the mean of the set is 20. The formula for the mean is (a + b + c + d + e) / 5 = 20.

We can simplify this to a + b + d + e = 80 (since we already know that c = 18).

Now we need to maximize the value of e, since that will give us the greatest possible integer in the set.

One way to do this is to minimize the values of a, b, and d.

Since we want all of the integers to be different, the smallest possible values for a, b, and d are 1, 2, and 3 (in some order).

So we have the following system of equations:

a + b + 18 + d + e = 80

a ≠ b ≠ d ≠ e

a ≥ 1, b ≥ 2, d ≥ 3, e ≥ 4

To maximize e, we should minimize the sum a + b + d. The only way to do this is to choose a = 1, b = 2, and d = 3.

Substituting these values into the first equation, we get:

1 + 2 + 18 + 3 + e = 80

e = 56

Therefore, the greatest possible integer in the set is 56. The set itself is {1, 2, 18, 3, 56}.

For similar question on greatest possible integer in the set.

https://brainly.in/question/2584518

#SPJ3