a set of n numbers has the sum S. Each number of the set is increased by 20 then multiplied by 5 and then decreased by 20. Then the sum of the numbers in the new set thus obtained is____
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Answered by
22
There are n numbers
Sum = S
Each number of the set is increased by 20
x+20
.....then multiplied by 5
5(x+20) = 5x + 100
........ and then decreased by 20
5x + 100 - 20 = 5x + 80
Essentially each number has been multiplied by 5 and increased by 80
The sum of the numbers in the new set = 5S + 80n
Sum = S
Each number of the set is increased by 20
x+20
.....then multiplied by 5
5(x+20) = 5x + 100
........ and then decreased by 20
5x + 100 - 20 = 5x + 80
Essentially each number has been multiplied by 5 and increased by 80
The sum of the numbers in the new set = 5S + 80n
Answered by
6
Answer:
Step-by-step explanation:
There are n numbers
Sum = S
Each number of the set is increased by 20
x+20
.....then multiplied by 5
5(x+20) = 5x + 100
........ and then decreased by 20
5x + 100 - 20 = 5x + 80
Essentially each number has been multiplied by 5 and increased by 80
The sum of the numbers in the new set = 5S + 80n
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