Question

 A set of two resistors of 4 ohm and 6 ohm connected in parallel is connected to another resistor of 1.6 ohm in series.The equivalent resistance of the combination will be-
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Answer 1

Explanation:

Given,

Resistance, R

A

=4Ω

Resistance,R

B

=6Ω

Voltage,V=6V

i) As resistance are connected in parallel

Equivalent resistance =

R

1

=

R

A

1

+

R

B

1

2

1

=

4

1

+

6

1

=

24

10

R=2.4Ω

As power,P=

R

V

2

=

2.4

(6)

2

=15w

ii) Power dissipation across each resistor, p=VI

Current acorss resistor R

A

.I

A

=

R

A

V

I

A

=

4

6

=1.5A

Power dissipation across resistor R

A

P=VI

A

=6×1.5=9w

iii) Current across resistor R

B

.I

B

=

R

B

V

I

B

=

6

6

=1A

Power dissipation accross resistor R

B

P=VI

B

=6×1=6w