Question

a shaft of a motor is making 1260rpm.the torque supplied by the motor is 100Nm .the power of the motor is (in KW

Answer 1

Angular speed = 1260 rpm
= (1260 × 2 π) rad / minute
= [(1260 × 2 π)/60] rad/s

Power = Torque × Angular speed
= 100 Nm × [(1260 × 2 π)/60] rad/s
= 13.188 kW

Answer 2

$angular \: velocity = 1260 \times( \pi \div 30) \frac{rad}{sec} \\ = 42\pi \frac{rad}{sec} \\ power = torque \times angular \: velocity \\ so \: power = 100 \times 42\pi =13.188kw$