A sheet of metal has dimension 56cm by 33cm. It is melted down and recast into discus of the same thickness and radius 7 cm. How many discs will be cast?
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Answered by
95
Given, thickness of metal sheet and disc is same.
Let thickness of metal sheet and disc be 't' cm.
Length of sheet=56 cm
Breadth of sheet=33 cm
Volume of sheet= length* breadth * thickness
= (56*33*t) cm³ =(1848*t) cm³
Radius of disc=r=7 cm
Volume of 1 disc(cylinder in shape)=πr²t =(22/7)*7²*t =(154*t) cm³
Assume number of discs that can be casted is n.
Volume of sheet=Volume of n discs
1848*t=n*154*t
1848=n*154
n=1848/154
n=12
Number of discs that can be casted is 12.
Let thickness of metal sheet and disc be 't' cm.
Length of sheet=56 cm
Breadth of sheet=33 cm
Volume of sheet= length* breadth * thickness
= (56*33*t) cm³ =(1848*t) cm³
Radius of disc=r=7 cm
Volume of 1 disc(cylinder in shape)=πr²t =(22/7)*7²*t =(154*t) cm³
Assume number of discs that can be casted is n.
Volume of sheet=Volume of n discs
1848*t=n*154*t
1848=n*154
n=1848/154
n=12
Number of discs that can be casted is 12.
Answered by
83
Volume =56×33
Area of the circle =22/7×7×7
= 154
Cast of the disc =56×33/154
=12
Area of the circle =22/7×7×7
= 154
Cast of the disc =56×33/154
=12
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