Question

A sheet of paper is in the form of a rectangle ABCD in which AB = 40 cm, and
BC = 28 cm. A semicirclular portion with BC as diameter is cut off. Find the area
of the remaining paper.​

Answer 1

Answer:

Step-by-step explanation:

area of the rectangle= 40*28 cm= 1120cm^2

area of semicircular area= πr^2/2

                                         = 22/7*14*14 divided by 2

                                         = 696cm^2/2

                                         =348 cm^2

Area of the left portion of sheet is  1120-348= 772 cm^2

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Answer 2

Area of rectangular sheet of paper = Area of rectangle = length × breadth = 40 × 28 = 1120 cm2 Area of semicircular cut out = 1/2 πr2 = 1/2 x 22/7 x 14 x 14 = 308 cm2 Now, Area of remaining sheet of paper = Area of rectangular sheet of paper – Area of semicircular cut out = 1120 – 308 = 812