A sheet of paper is in the form of a rectangle ABCD in which AB= 40 cm and AD=28 cm. A semicircle portion with BC as diameter is cut off, find the area of the remaining paper?
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the area of the remaining paper is 812 sq.cm
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Answer:
Length of paper, AB = l = 40cm
Width of paper, AD = b = 28cm
Area of paper = l × b = 40 × 28 = 1120 cm²
Diameter of semi-circle = 28cm
∴ Radius of semi-circle, r = 14cm
Thus, area of semi-circle = 1/2 πr²
= 1/2 × 22/7 × 14 × 14
= 308 cm²
∴ Area of remaining paper = 1120 – 308
= 812 cm²
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