Question

A sheet of paper is in the form of rectangle ABCD in which AB = 40cm and AD = 28 cm. A semicircular portion with BC as diameter is cut off. Find the area of remaining paper.

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Answer 1

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▪️First find the ar of the rectangle ABCD

▪️=28×40

▪️=1120

▪️Then fimd the ar of semicircle=1/2 of circle

▪️=22/7*1/2*14

▪️=308

▪️Then subtract=arof ABCD-ar of semi cirlcle

▪️ =1120-308

▪️ =812

▪️ This is the remaining ar of paper

Hopes it help you✌️✌️

Answer 2

Qᴜᴇsᴛɪᴏɴ :

➥ A sheet of paper is in the form of rectangle ABCD in which AB = 40cm and AD = 28 cm. A semicircular portion with BC as diameter is cut off. Find the area of remaining paper.

Aɴsᴡᴇʀ :

➥ The area of remaining paper = 812 cm²

Gɪᴠᴇɴ :

➤ Length of paper AB = 40 cm

➤ Width of paper AD = 28 cm

Tᴏ Fɪɴᴅ :

➤ The area of reaming paper = ?

Sᴏʟᴜᴛɪᴏɴ :

Diameter of semicircle = 28 cm

Therefore, radius = $\sf{\dfrac{\cancel{28}}{\cancel{\:2\:}}}$ = 14 cm

Now,

Area of remaining paper = (Area of rectangle) - (Area of semicircle)

☛ Putting values

$\sf{:\implies (ab \times bc) - \left(\dfrac{1}{2} \pi {r}^{2} \right) }$

$\sf{:\implies (40 \times 28) - \left(\dfrac{1}{2} \times \dfrac{22}{7} \times14 \times 14 \right) }$

$\sf{:\implies 1120 - 308}$

$\sf{:\implies \underline{\overline{\boxed{\purple{\bf{ \:\:812 \: {cm}^{2}\:\: }}}}}}$

Hence, the remaining paper is 812 cm².