Question

A shell has charge 10q at its center. AB is diameter of it. How much work is needed to move a charge q from A to B?​

Answer 1

Answer:

Work done = Change in P.E.

Change in P.E. ΔU=

R+r

KQq

−0

where K=9×10

9

,

Q=σ4πr

2

=16π×10

−4

C

q=40×10

−9

C,

Putting all the values we get,

W=

4×10

−2

9×10

9

×16π×10

−4

×40×10

−9

W=14.4π J