Question

A shell is fired at an angle of 30 degree to the horizontal with velocity of 196m/s. Find the horizontal range

Answer 1

Answer:The maximum height is obtained as 1960m. Hence, 1)The horizontal range is 13579.27m. 2)The time of flight is 40 seconds.

Explanation:

Answer 2

To Find :-

• The horizontal range.

Solution :-

Given,

A shell is fired,

• Angle($\bold{\theta}$) = 30°
• Velocity (u) = 196 ms-¹
• Acceleration due to gravity (g) = 9.8 ms-²

The horizontal range formula is given as ;

$\sf{R = \dfrac{u^2sin2\theta}{g}}$ $\red\bigstar$

[ Put the values ]

$\longrightarrow \sf \: R = \dfrac{(196) {}^{2} \times sin 2 (30\degree)}{9.8}$

$\longrightarrow \sf \: R = \dfrac{38416 \times sin60 \degree}{ 9.8}$

$\longrightarrow \sf \: R = \dfrac{38416 \times \frac{ \sqrt{3} }{2} }{9.8}$

$\longrightarrow \sf \: R = \dfrac{19208\times \sqrt{3} }{9.8}$

$\longrightarrow \sf \: R = 1960 \sqrt{3} \: m \: \green \bigstar$

Therefore,

The horizontal range is 1960√3 m.