a shell is fired at an angle of 30 degree with the velocity of 392 metre per second find the horizontal range time of flight and maximum height attained
Answers
Answer:
1)The horizontal range is 13579.27m.
2)The time of flight is 40 seconds.
3) The maximum height is obtained as 1960m.
These are the correct answers.
Explanation:
A shell is fired.
angle = 30 °
Velocity = 392 metre/second
g= 9.8m/s^2
To find:
1) the horizontal range
2)time of flight and
3) maximum height attained
Solution:
The horizontal range is given by the formula
R = u*^2sin2theta/g
= 392*392*sin60/9.8
=133076.92/9.8
=13579.27 m
The horizontal range is 13579.27m.
The time of flight is given by the formula
T= 2usintheta/g
= 2*392*sin30/9.8
=392/9.8
=40 seconds.
The time of flight is 40 seconds.
The maximum height is given by the formula
H= u^2sin^theta/2g
= 392*392*sin30*sin30/2*9.8
=38416/19.6
=1960 m
The maximum height is obtained as 1960m.
Hence,
1)The horizontal range is 13579.27m.
2)The time of flight is 40 seconds.
3) The maximum height is obtained as 1960m.
These are the correct answers.
Explanation:
hope it will help you
