A shell is fired from a canon with a velocity v at an angle theta with the horizontal direction at the highest point in its path it explodes into two pieces of equal masses one of the peace retraces its path to the canon the speed of the other piece immediately after the explosion
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A shell fired at angle ′θ′′θ′ velocity of shell at highest point is vcosθvcosθ
Let its mass be m
speed of one piece =vcosθ=vcosθ
Let speed of other piece =v′=v′
Using conservation of momentum
mvcosθ=m2mvcosθ=m2vcosθ+m2v′vcosθ+m2v′
Therefore v′=3vcosθv′=3vcosθ
Hence a is the correct answer.
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