A shell is fired from a gun with muzzle velocity u m/s at an angle theta with the horizontal. At the top of trajectory the shell explodes into 2 fragments P and Q of equal mass. If speed of P fragment immediately after explosion becomes zero, where does the centre of mass of the fragments hit the ground from point of projection?
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Answer:
Let v' be the velocity of second fragment. From conservation
of linear momentum,
2 m (v cos
v ' = 3 cos
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