Question

A shell is fired from point o at an angle of 60° with the horizontal with the speed 40 m/s

Answer 1

Explanation:

ANSWER

During a projectile motion, horizontal velocity component is given by ucosθ.

The horizontal component of velocity u is ucosθ.

The horizontal component of velocity at the highest point is thus ucosθ.

Using momentum conservation,

2mu=mv

1

+mv

2

⇒2mucosθ=−mucosθ+mv

2

⇒mv

2

=2mucosθ+mucosθ=3mucosθ

⇒v

2

=

m

3mucosθ

=3ucosθ