Question

a shell is fired with v=100m/s at an angle of 30°with horizontal.at heighest point it explodes in two parts of mass ratio 1:2 just after explosion smaller part start to move with 50m/s upward find out speed of havier part after eexplosion​

Answer 1

Answer:

25m/s.

Explanation:

Conservation of momentum

m1*v1=m2*v2