Question

A shell is weighing 800 kg is fired horizontally with a velocity of
500 m/sec. From a gun weighing 50 tonne. With what initial
velocity, the gun will recoil? What average force will be required
to bring it to rest if it is allowed to move through one meter?​

Answer 1

Answer:

25600 newton

Explanation:

Recoil velocity = - 8m/s (use conservation of momentum)

V=0, u= - 8m/s, s=1m use eqn of motion and your a =32m/s

F=MA = 800 * 32= 25600