Question

A shell of mass 0.020 kg is fired by a gun of mass 100 kg . if the muzzle speed of the shell is 80 ms -1 ,what is the recoil speed of gun ?

Answer 1

Given:
Mass of gun=M=100kg
mass of shell =m=0.020kg
Velocity of shell = v=80m/s
Recoil velocity of Gun=V=?
initial velocities of both gun and shell will be zero
so, initial momentum of system will be zero.
According to the law of conservation of momentum,
Initial momentum=Final momentum
so,
0=mv-MV
∴v=mv/M
=0.020x80/100
=0.016m/s
∴recoil velocity of Gun=0.016m/s

Answer 2

☺Hello friend____❤

✒Your answer is here⤵

Mass of the gun, M = 100 kg

Mass of the shell, m = 0.020 kg

Muzzle speed of the shell, v = 80 m/s

Recoil speed of the gun = V

Both the gun and the shell are at rest initially.

Initial momentum of the system = 0

Final momentum of the system = mv – MV

Here, the negative sign appears because the directions of the shell and the gun are opposite to each other.

According to the law of conservation of momentum:

Final momentum = Initial momentum

mv – MV = 0

V = mv/M = ( 0.020× 80)/(100× 1000)

= 0.016 m/s

I hope, this will help you

Thank you_____❤

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