A shell of mass 0.02kg is fired by a gun of mass 100kg. If the muzzle speed of the shell is 80m/s. What is the recoil speed if the gun?
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m = 0.02 kg, M = 100 kg, v = 80 m/s
Let V be the recoil speed of the gun
According to the law of conservation of momentum
,Initial momentum = Final momentum0 = mv + MVV =
- mv/M
= - 0.02 x 80/100
= - 0.016 m/s
Let V be the recoil speed of the gun
According to the law of conservation of momentum
,Initial momentum = Final momentum0 = mv + MVV =
- mv/M
= - 0.02 x 80/100
= - 0.016 m/s
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