Question

A shell of mass 10 kg moving with a velocity of 20 metre per second explodes into two portion of 6 kg and 4 kg respectively if the former is just brought to rest after explosion find the velocity of later​

Answer 1

Answer:

According to Law of Conservation of Linear momentum

mV = m1V1 + m2V2

V1 =0

10× 20 = 4v

v = 50m/sec

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Answer 2

The velocity of the 4 Kg portion of the mass = 50 m/s

Initial momentum of the shell = mv = 10 × 20 = 200 Kg m/s

The shell explodes into two particles of mass 6 Kg and 4 Kg . The 6 Kg mass will come to rest (v1) and let the velocity of 4 Kg mass be v2.

Final momentum = m1v1 + m2v2

= 0 + 4v2

Acoording to law of conservation of momentum the initial and the final momentum will be equal.2

=> 4v2 = 200

=> v2 = 50 m/s