Question

A shell of mass 10kg is fired from a gun of mass 600kg . The gun recoil with a velocity of 6m/s. Find the muzzle velocity of the shell

Answer 1

Given :

▪ Mass of gun = 600kg

▪ Mass of shell = 10kg

▪ Recoil velocity of gun = 6m/s

To Find :

▪ Muzzle velocity of shell.

Concept :

▪ Since, No net force acts on the system, we can easily apply concept of momentum conservation to solve this question.

▪ Initial momentum of system = Final momentum of system

Here, Initial momentum = zero

Calculation :

→ (P)initial = (P)final

→ 0 = MV + mv

where,

M denotes mass of gun

V denotes recoil velocity of gun

m denotes mass of shell

v denotes velocity of shell

→ [600 × (-6)] + [10 × v] = 0

(-ve sign shows opposite direction)

→ 10v = 3600

→ v = 3600/10

→ v = 360m/s

Answer 2

Answer :

• velocity of the shell is 360 m/s

Given :

• A shell of mass 10 kg is fired from a gun of mass 600 kg . The gun recoil with a velocity of 6 m/s

To Find :

• The muzzle velocity of the shell

Solution :

Simply apply law of conservation of momentum.

$\implies \bf Initial\ momentum=Final\ momentum\\\\\implies \bf (M_s+M_g)0=M_s.V_{s}-Mg.V_{recoil}\\\\ \implies M_g.V_{recoil}=M_s.V_{s}\\\\\implies \bf 600*6=10*V_s\\\\\implies \bf 360=V_s\\\\\implies \bf V_s=360\ m/s$

So , velocity of the shell is 360 m/s