Question

A shell of mass 200 g is ejected from a gun of mass 4 kg by an explosion that generates 1.05 kJ of energy. The initial velocity of the shell is :​

Answer 1

$\small \bold{ \frac{E_1}{E_2} = \frac{m_2}{m_1} \implies \frac{4}{0.2} = 20 \implies \: E_2 = \frac{E_1}{40} }$

$\bold{E_1 + E_2 = 1050 \: joule}$

$\small \bold{ \therefore \: E_1 =1000 \: joule \: (energy \: of \: cell)}$

$\small\bold{ \therefore \: K.E. \: of \: shell = \frac{1}{2} \times m_1v {}^{2} _1}$

$\bold{1000 \times \frac{1}{2} \times (0.2) \times v {}^{2} _1}$

$\bold{ \therefore \: V_1 = \sqrt{10000} = 100 \: m/s}$

Answer 2

Hence speed of bullet is 100m/s

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