Question

A shell of mass m moving with a velocity v suddenly explodes into two pieces. One part of mass m/4 remains stationary. The velocity of other part is

Answer 1

Answer:

mass of two pieces m/4  and 3m/4

mv=m/4*0+3m/3v

v=4v/3

Explanation:

Answer 2

Answer:

The velocity of the other piece is 4v/3 ms⁻¹

Explanation:

Given;

    Complete mass = m

       Mass at rest = m/4

Remaining mass = m - m/4 = 3m/4

 velocity =v m/s

Let the velocity of the remaining piece be v₁.

Now, we know that, by formula that;

      Initial Momentum = Final momentum (for given case)

           mv = m/4 ×0 + 3m/4 × v₁

              v = 3/4 × v₁

              v₁ = 4v/3 ms⁻¹

Hope it helps! ;-))