Physics, asked by evapauly6771, 5 hours ago

A shell weighing 24 kg is fired from a gun weighing 720 kg with a velocity of 60 m/s. Find velocity of recoil of the gun.

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Answered by gyaneshwarsingh882

Answer: For example

$By the law of conservation of momentum,\\Initial momentum = find momentum\\∴P \\1 =P 2 ∴m\\ 1\\ v 1 =m 2 v 2 here, m 1 =20gm.v 1 =200ms −1 ,m 2 =20kg=20,000gm∴v 2 = m 2 m 1 v 1 = 20,00020×200 ∴ v 2 =0.2 m/s$

$Let the recoil velocity of gun be V.\\Mass of gun M gun =5.0 kg \\ Mass of bullet M bullet =0.01 kg\\Velocity of bullet V bullet =250 m/s\\Initial momentum of the system P i =0\\Applying the conservation of linear momentum : P f =P i Or M gun V+M bullet V bullet =0Or 5×V+0.01×250=0⟹ V=−0.5 m/s$

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