A shepherd has 200 sheep with him. Find the number of sheep's with after 3 yrs if the incrase in number of sheep's is 8% every years?
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Answer:
the number of sheeps after 3 years is 252.
Explanation:
Here, P = No. of sheeps initially = 200
A = no. of sheeps after 3 yrs
R = Rate of increase of no. of sheeps per year = 8%
N = 3 yrs
= 252(approx)
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Here is your answer
every year 8% sheeps are increasing thus
We will find how many sheeps increases every year
so we can find it bye multiplying 200 by 8%
that is
200 × 8/100
it gives 16 . This means every yar 16 sheeps are increasing
thus in 3 years 3 × 16 = 48 sheeps will increase
so total no. of sheeps after 3 years will be
200 + 48 = 248 sheeps
248 is the required answer
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