A shepherd has 200 sheep with him .Find the number of sheep s with him after 3 years if the increase in number of sheeps is 8% every year .Tell answer
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Answer:
Step-by-step explanation:
The number of sheeps with him after 1 year = 200+(8%of 200).
= 200+[(8/100)×200].
= 200+(8×2).
= 200+16.
= 216.
The number of sheeps with him after 2 years = 216+(8%of 216).
= 216+[(8/100)×216].
= 216+(8×2.16).
= 216+17.28.
= 233.28.
No.of sheeps cannot be in decimal form, so the no. of sheeps with him after 2 years will be 233.
The number of sheeps with him after 3 years = 233+(8%of233).
= 233+[(8/100)×233].
= 233+(8×2.33).
= 233+18.64.
=251.64.
No.of sheeps cannot be in decimal form, so the no. of sheeps with him after 3 years will be 251.
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