A shepherd has 200 sheep with him. Find the number of sheeps with him after 3 years if the increase in number of sheeps is 8% every years
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in C.I.
A = P(1+R/100) race to 3
=200×108÷100+108÷100+108÷100
=218.6
the sheep's can't be 218.6 so they are 219(approx.
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Answer:
Here, P = Number of sheeps initially = 200
A = Number of sheeps after 3 years
R = Rate of increase of number of sheeps per year = 8 %
N = 3 years
A = P × (1+R/100)N
=200 × (1+8/100)³
=200 × (1+2/25)³
=200 × (27/25)³
=251.94
=252 (approx)
Hence, the number of sheeps after 3 years is 252
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