Question

a shepherd has 200 sheeps with him find the number of sheeps with him after 3 years if the increase in number of sheeps is 8% every year​

Answer 1

Sheep's Now=200

Rate of Increase=8% annually .

Means If There is 1 sheep Increasing with 8% .In first Year it will 8.In second year it will 8% of 8.And increasing Like this.

You can Use This Formula.

$sheeps \: now(1 + \frac{rate}{100} ) {}^{time}$

Rate=8%

Time=3 years

Now

$200(1 + \frac{8}{100} ) {}^{3} \\ \\ 200( \frac{108}{100} ) {}^{3} \: \: \: (lcm = 100)\\ \\ \\ \\ 2\cancel{00} \times \frac{108}{1\cancel{00}} \times \frac{108}{100} \times \frac{108}{100} \\ \\ 2 \times 108 \times \frac{\cancel{108}}{\cancel{100}} \times \frac{\cancel{108}}{\cancel{100} } \\ \\ 2 \times 108 \times \frac{27}{25} \times \frac{27}{25} \\ \\ 2 \times 108 \times \frac{729}{625} \\ \\ =251.94$

Sheep After 3 years=251.94

Approx=252 sheep's.

$\boxed{\mathtt{\huge{Sheep=252}}}$

Answer 2

Please mark as brain list