Question

A ship anchored in a port has a ladder which hangs over the side. The length of the ladder is 200cm, the distance between each rung in 20cm and the bottom rung touches the water. The tide rises at a rate of 10cm an hour. When will the water reach the fifth rung? ​

Answer 1

Answer:

10 HRS

Step-by-step explanation:

FIFTH RUNG = 20 * 5 = 100 CM

AMT RISEN IN EACH HR = 10 CM

  SO THE NO OF HOURS IT TAKES FOR THE WATER TO RISE TO THE FIFTH RUNG= 100/10 =  10 HRS

Answer 2

Given : A ship anchored in a port has a ladder that hangs over the side . the ladder is 200cm  long and distance between each rung is 20 cm and the bottom ring touches the water

The tide rises at the rate of 10 cm an hour.

To Find : when will the water reach the fifth rung

Solution:

the bottom ring touches the water

if bottom rung is first rung

Then water to rise  for  4 rungs to reach fifth rung

Distance in 4 rungs =  20 * 4 = 80 cm

The tide rises at the rate of 10 cm an hour.

Hence time = 80/10 = 8 hrs

if bottom rung is zeroth rung

Then water to rise  for  5 rungs to reach fifth rung

Distance in 5 rungs =  20 * 5 = 100 cm

The tide rises at the rate of 10 cm an hour.

Hence time = 100/10 = 10 hrs

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A ship anchored in a port has a ladder that hangs over the side

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