a ship covered A certain distance at a uniform speed if the speed of ship would have been 6 km per hour faster it would have taken 4 hours less than the scheduled time and if the speed of ship was lowered by 6 km per hour it would have taken 6 hours more than the scheduled time find the length of the journey
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Let t be the usual time taken by the ship to cover the distance
Let d be the distance, s be the usual speed
Usual time taken => d/s = t => d=ts
d/(s+6) = t-4
ts/(s+6) = t-4
ts = ts+6t-4s-24
6t - 4s - 24 = 0 --> (1)
d/(s-6) = t+6
ts = ts-6t+6s-36
-6t + 6s - 36=0 --->(2)
Solving (1) nd (2), we get
s = 30 km/h
t = 24 hrs
d = t × s
d = 30 × 24 = 720 km
•°• The Distance travelled by the ship is 720km
Let d be the distance, s be the usual speed
Usual time taken => d/s = t => d=ts
d/(s+6) = t-4
ts/(s+6) = t-4
ts = ts+6t-4s-24
6t - 4s - 24 = 0 --> (1)
d/(s-6) = t+6
ts = ts-6t+6s-36
-6t + 6s - 36=0 --->(2)
Solving (1) nd (2), we get
s = 30 km/h
t = 24 hrs
d = t × s
d = 30 × 24 = 720 km
•°• The Distance travelled by the ship is 720km
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