A ship covers a distance of 144c(a-6)(b-3) nautical miles every day . in how many day can it cover a distance of 72abc(2a square-12a) (5b-15)
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x(144c(a-6)(b-3))=72abc(2a square-12a) (5b-15)
x(2)=bc(2)5
x=5bc
no of days=5bc
x(2)=bc(2)5
x=5bc
no of days=5bc
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