Question

a ship is moving at 40 kilometre per hour towards west. another ship is proceeding towards south at 30 km per hour. find the relative velocity of the second ship with respect to the first ​

Answer 1

Explanation:

It is clear from the diagram that the shortest distance between the ship A and B is PQ.

Here, Sin45

0

=

OQ

PQ

⟹PQ=100×

2

1

=50

2

m

Also,

V

AB

=

V

A

2

+V

B

2

=

10

2

+10

2

=10

2

km/h

So, the time taken to reach shortest path is

t=

V

AB

PQ

=

10

2

50

2

=5h