Question

A ship is moving at a speed of 56 km/h. One second later, it is moving at 58 kmh. What is its acceleration ?
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Answer 1

Explanation:

Given:-

Initial velocity (u)=56 km/h

Final velocity (v)=58km/h

Time(t)=1 second

Solution:-

$\sf Acceleration = \dfrac{v-u}{t}$

$\sf Acceleration= \dfrac{58-56}{1}$

$\sf Acceleration = \dfrac{2}{1}$

$\sf Acceleration = {2kms}^{-1}$

Hope it helps

Answer 2

✯✯ QUESTION ✯✯

A ship is moving at a speed of 56 km/h. One second later, it is moving at 58 kmh. What is its acceleration ?

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✰✰ ANSWER ✰✰

$\implies\tt{Initial\:Speed(u)=56km/h}$

$\implies\tt{Final\:Speed(v)=58km/hr}$

$\implies\tt{Time\:Taken(t)=1s}$

$\implies\tt{Acceration(a)=?}$

➥Using 1st Equation of Motion : -

$\implies\tt{\large{\boxed{\bold{\bold{\green{\sf{v=u+at}}}}}}}$

➥Putting Values : -

$\implies\tt{58=56+a(1)}$

$\implies\tt{58=56+a}$

$\implies\tt{58-56=a}$

$\red\longmapsto\:\large\underline{\boxed{\bf\pink{a}\orange{=}\purple{2}}}$

☛So , The acceleration is 2km/s....