Question

a ship is moving at a speed of 56km/h .one second later, it is moving at 58 km/h . what is its acceleration ?

Answer 1

a = (v-u)/t

here

u = 56 km/hr = 15.56 m/s

v = 58 km/hr = 16.11 m/s

t = 1 sec

therefore,a = (16.11 - 15.56) / 1

thus,a = 0.55 m/s2

hope this will help...plz react thanks

Answer 2

Dear Student,

Let's see the data given:

Initial velocity(u) = 56 km/h
                           = 15.56 m/s
Final velocity(v)  = 58 km/h
                           = 16.11 m/s
Time(t) = 1 second

We know, 
Acceleration(a) = (v-u)/t
                         = (16.11-15.56)/1
                         = 0.55 m/s²  ← (Ans)