Question

A ship is moving at a speed of 56km/h . one second later , it is moving at 56km/h . what is acceleration ?​

Answer 1

Answer

• Acceleration , a = 0 m/s²

Given

• A ship is moving at a speed of 56 km/h . one second later , it is moving at 56 km/h

To Find

• Acceleration

Formula Used

• Acceleration is defined as rate of change in velocity

$\bigstar \;\; \bf a=\dfrac{v-u}{t}$

Solution

Initial velocity , u = 56 km/h = 56 × ⁵/₁₈ m/s = 15.56 m/s

Time , t = 1 s

Final velocity , v = 56 km/h = 15.56 m/s

Acceleration , a = ? m/s²

We have observed that initial and final velocities are same .

That is nothing but constant velocity .

• For a constant velocity , acceleration is zero .

Let's see ,

$\implies \rm a=\dfrac{v-u}{t}\\\\\implies \rm a=\dfrac{15.56-15.56}{1}\\\\\implies \rm a=\dfrac{0}{1}\\\\\implies \rm a=0\ m/s^2$

Answer 2

Solution :

We know that acceleration of body is Change in velocity /Time

According to the question the initiall velocity 0f the body is 56km/hr and the final velocity is also 56 km/hr

And time taken by ship= 1s,

Acceleration=v-u/t

=> final velocity -initiall velocity/Time

=> 56km/hr-56km/hr/1s

=> 0km/hr²

From this question we learnt that,

$accelertion \: of \: any \: body \: will \: be \: zero \: when \: the \: final \: and \: initiall \: velcity \: is \: 0$

$when \: initall \:and \: finl \: velocity \: is \:same$