Question

A ship is moving at a speed of 56km/h . One second later , it is moving at 58km/h . What is it's acceleration ? 

Answer 1

Given:
Method I:
Initial speed=u=56km/h=56 x 5/18=15.55m/s
Final speed=v=58km/h=58x5/18=16.11m/s
Time=t=1sec
acceleration=a=?
as we know that acceleration is rate of change of velocity.
a=(v-u)/t
=(16.11-15.55)/1
=0.56 m/s²

Method 2:
Initial speed=u=56km/h
Final speed=v=58km/h
Time=t=1/60x60 h
acceleration=a=?
as we know that acceleration is rate of change of velocity.
a=(v-u)/t
=(58-56)/1/60*60
=2x3600
=7200 Km/h²
∴ Acceleration is 0.56 m/s² or 7200 Km/h²

Answer 2

Answer:

Explanation:

Given :-

Initial speed of the ship, u = 56 km/h

Final speed of the ship, v = 58 km/h

Time taken by ship, t = 1/60 × 60 h

To Calculate :-

Acceleration of ship, a = ??

Formula to be used :-

1st equation of motion

i.e, v = u + at

Solution :-

Putting all the values, we get

v = u + at

⇒ a = v - u/t

⇒ a = 58 - 56/1/60 × 60

⇒ a = 7200 km/h²

In metres/second

⇒ a = 0.56 m/s²

Hence, the acceleration of ship is 7200 km/h² in km/h and 0.56 m/s² in m/s.