Question

a ship is moving at a speed of 56km/h. one second later it is moving at a speed of 58km/h.what is its acceleration

Answer 1

we know that acceleration (a) = final velocity (v) - initial velocity (u) divided by time taken (t)
so v = 58km/hr = 16 m/s
u = 56 km/hr = 15 m/s
t = 1 second
a = 16 - 15 / 1
a = 1m2/s

Answer 2

Answer:-

Explanation:

Given:-

Initial Speed (u) = 56 km/h

Final Speed (v) = 58 km/h

Time Taken (t) = 1 sec = 1/60 × 60 h

To Calculate:-

Acceleration (a)  = ???

Formula to be used:-

Acceleration (a)  = v - u/t

Solution:-

⇒ Acceleration (a)  = v - u/t

⇒ Acceleration (a)  = $\frac{58-56}{\frac{1}{60X60} }$

⇒ Acceleration (a) = 7200 km/h = 0.56 m/s²

Hence, the acceleration is 0.56 m/s².