Question

A ship is moving at a speed of 56km/h . One second later, it is found to be moving at 58km/h, what is the acceleration of the ship?

Answer 1

Given:Method I:Initial speed=u=56km/h=56 x 5/18=15.55m/sFinal speed=v=58km/h=58x5/18=16.11m/sTime=t=1secacceleration=a=?as we know that acceleration is rate of change of velocity.a=(v-u)/t=(16.11-15.55)/1=0.56 m/s²
Method 2:Initial speed=u=56km/hFinal speed=v=58km/hTime=t=1/60x60 hacceleration=a=?as we know that acceleration is rate of change of velocity.a=(v-u)/t=(58-56)/1/60*60=2x3600=7200 Km/h²∴ Acceleration is 0.56 m/s² or 7200 Km/h

Answer 2

u=56km/h
v=58km/h
t=1 sec
a=(v-u)/t
a=2m/sq.