Question

A ship is moving at a speed of 56km/hr.one second lateer it is moving at 58km/hr.find its acceleration

Answer 1

Hey.

Here is the answer.

u = 56km/h = 56×5/18 m/s = 140/9 m/s

v= 58km/h = 58×5/18 m/s =145/9 m/s

t =1 s

As V =u + a t

so, 145/9 =140/9 + a × 1

or, 145/9 -140/9 = a

or, 5/9 = a

so, acceleration = 5/9 m/s^2 =0.555 m/s^2

Thanks.