Question

A ship is moving towards N-E with a velocity of
10 km/hr and to a passenger on board the wind
appears to blow from the north with a velocity of
10√2 km/hr. Actual velocity of the wind is​

Answer 1

Vpw=vp-vw

-10√2j=10(i+j/√2)-vw

-10√2j=5√2i+5√2j-vw

(-10√2-5√2)j+(-5√2)i= -vw

15√2j+5√2i=vw

vw= 10√5km/hr

Answer 2

Answer:

$v_w$ = $10\sqrt 5 \frac{km}{hr}$

Explanation:

In this question

Given that

Vector velocity of the ship is $v_p$ = $10 \frac{km}{hr}$

Velocity  of the ship relative to the wind $v_pw$

Formula, $v_pw$ = $v_p - v_w$

$-10\sqrt 2 j$ = $-10(i + j)\times \sqrt 2 j$ - $v_w$$-10\sqrt 2 j$ = $5\sqrt 2 j$ + $5\sqrt 2 i$  - $v_w$

$(-10\sqrt 2 - 5\sqrt 2)j$ + $(-5\sqrt 2)i$ = -$v_w$

$(15\sqrt 2)j$ + $(5\sqrt 2)i$ = $v_w$

$v_w$ = $10\sqrt 5 \frac{km}{hr}$