Question

A ship is moving with a constant acceleration of 36 km/hr in a fixed direction speeds up from 18 km/hr to 36 km/hr. Find the distance traversed by the ship in this period?​

Answer 1

Explanation:

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Answer 2

Answer:

Given,

Acceleration, a=36km/h

2

Initial velocity, u=12km/h

Final velocity, v=18km/h

Using the equation of motion as:

v

2

−u

2

=2as

Where, s is distance traversed by ship.

(18)

2

−(12)

2

=2(36)s

324−144=36s

s=5km

Distance traversed by ship is 5 Km.