Question

A ship is moving with speed of 56km/h.One second later ,it is found to be moving at 58 km/h,what is the acceleration of ship

Answer 1

u=56 km/h = 56*1000/60*60=140/9 m/s
v=58 km/h = 58*1000/60*60=145/9 m/s
t=1 s
a=(v-u)/t=(145/9-140/9)/1=(5/9)/1=5/9 m/s or 0.56 m/s

Answer 2

Let's see the data given:

Initial velocity(u) = 56 km/h

                          = 15.56 m/s

Final velocity(v)  = 58 km/h

                          = 16.11 m/s

Time(t) = 1 second

We know,

Acceleration(a) = (v-u)/t

                        = (16.11-15.56)/1

                        = 0.55 m/s²  ← (Ans)