Question

a ship is traveling due east at 10 km per hour. A ship heading 30 degree east of north is always due north from the first ship. The speed of the second shift in kilometre per hour is

Answer 1

Answer:

Explanation:two components is v1 in north nad v2(in east....as net b/w north n east).

as original speed at 30deg east of north so, so perpendiculat to it zero velocity.

v1sin30= v2sin60 .........................1

also by relative concept as relative to other ship dirn is north so zero vel along east west direction...it gives

v2=10

then x=10/sin(30º)=10/1/2=20 km/h

Answer 2

Explanation:

Let the speed of ship be x,

Thus x×cos60=10 (since the ship is always north of the ship due east)

thus

2

x

=10

Therefore, speed of the second ship, x=20km/h