Question

A ship is traveling due east at 10km/h. What must be the speed of a second ship heading 30 degree of north it it is always due north from the first ship?

Answer 1

Answer:

Here is u r Answer

Two components is v1 in north and v2 in east as original speed at 30°⟶east of north.

So, perpendicular to it, zero velocity.

 v1sin30°=v2sin60°−−−−−−(i)

Also, v2=10

Then, x=sin30°10=(21)10=20km/h

20km/h

MARK AS BRAINLIEST

Answer 2

please see the attachment here....