A ship is travelling due east at 10 km/h. A ship heading 30° east of north is always due north from the first
ship. The speed of the second ship in km/h is -
Answers
Answered by
2
Answer:
20
Explanation:
Two components is v
1
in north and v
2
in east as original speed at 30°⟶east of north.
So, perpendicular to it, zero velocity.
v
1
sin30°=v
2
sin60°−−−−−−(i)
Also, v
2
=10
Then, x=
sin30°
10
=
(
2
1
)
10
=20km/h
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