Math, asked by jaanakhan, 10 months ago

A ship leaves a port and travels 12 km due east then it turns and travels 9 km due north how far is the ship from the port

Answers

Answered by santy2
59

Answer:

The ship is 15 km from the port.

Step-by-step explanation:

When you visualize the path taken by the ship you realize that it forms a right angled triangle with sides 12 km and 9 km.

The distance between the ship from the port at the final destination is given by the hypotenuse of the right angled triangle formed.

We can get the hypotenuse of the right angled triangle by Pythagorean theorem.

Let the hypotenuse by h.

The distance between the ship and the port is given by:

h = √(12² + 9²)

h = 15 km

Therefore, the ship is 15 km from the port.

Answered by girishtab09
2

Answer:

Going 12 km east, and then 9 km north, the distance of the ship from its’ starting position can be seen as the hypotenuse of a right triangle with legs of 12 and 9. The hypotenuse would be √9²+12²=√81+144=√225= 15 km

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